喷枪结构图:(1+x)^(1/x) when x close to infinity
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用f(x)denate the function
then
you can get
f(x)=e^(ln(f(x)))
then you can get the answer
Good luck!
令y=(1+x)^(1/x)两边取对数得:
lny=[ln(1+x)]/x,又知,lim[ln(1+x)]/x(上下同取导数)=lim[1/(1+x)],因此,当x无穷大时,lny=0则,y=1,得解!
x趋向无穷大,即1/x趋向于0
所以为1
e
(x*x*x-x*x+x)/(x*x*x+1)+(x*x+x+1)/[(1-x*x)/x)]
(x*x*x-x*x+x)/(x*x*x+1)+(x*x+x+1)/[(1-x*x)/x)]
已知x*x-3x+1=0,求x*x+1/x*x
解一元二次方程X*X+1/X*X+X+1/X=0
当1<x<2时化简| x-1|/1-x-x/|x|-|x-2|/2-x
5x-2/(x+2)(x-2)-(x-1)(x+2)/(x+2)(x-2)=0
计算[(x-1)/(x-2)-(x-2)(x-3)-(x-3)/(x-4)+(x-4)(x-5)]/(2x-7)
已知x+1/x =4,则x^2/x^4+x^2+1
X^2-2X-1=0,X<0问X+1/X=?
x*(x/3)=(x-5)*(x/3+1)/2 x=?