择天记吴曼思:不等式的问题
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求不等式(x-3)/5-(x-1)/2≤1的负整数解
(x-3)/5-(x-1)/2≤1
2(x-3)-5(x-1)<=10
-3x<=11
x>=-11/3
负整数解是x=-3,-2,-1.
左右两边同乘以10:
2X-6-5X+5≤10
-3X≤11
所以负整数解为:
X=-3,-2,-1
(x-3)/5-(x-1)/2≤1
2(x-3)-5(x-1)<=10
-3x<=11
x>=-11/3
x>-3.6
负整数解是x=-3,-2,-1.
解:
2(X-3)-5(X-1)≤10
X≥-11/3
X=-3,-2,-1